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  1. Prepare
  2. Artificial Intelligence
  3. Probability & Statistics - Foundations
  4. Day 3: Basic Probability Puzzles #7
  5. Discussions

Day 3: Basic Probability Puzzles #7

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  • singhjaitawat824
     + 0 comments

    from fractions import Fraction

    a = Fraction(5, 1000) b = Fraction(8, 1000) c = Fraction(10, 1000)

    prob_a = ((a*500)/3500) prob_b = ((b*1000)/3500) prob_c = ((c*2000)/3500)

    prob = Fraction(prob_a/(prob_a + prob_b + prob_c))

    print(prob)

  • pablosepulvedan1
     + 0 comments

    Python I multiplied every production 2 times cause in A there are 2.5 defective units, times 2 --> 5 units

    from fractions import Fraction


A = 500*2
pA = 0.005

defA = ['defA' for _ in range(int(A*(pA)))]

B = 1000*2
pB = 0.008

defB = ['defB' for _ in range(int(B*(pB)))]


C = 2000*2
pC = 0.010

defC = ['defC' for _ in range(int(C*(pC)))]

totalDef = defA + defB + defC

count=0

for pipe in totalDef:
    if pipe=='defA':
        count += 1
        
print(Fraction(count, len(totalDef)))

  • faezeh_jahanmiri
     + 0 comments

    I got a different answer. P(A|defect)=P(A and defect)/P(defect) P(A and defect) is 5/1000 P(defect)=(0.005*500+0.008*1000+0.01*2000)/3500 = 61/7000

    so P(A|defect) = 5/1000 / 61/7000 = 35/61 ??

  • shinde_shekhar11
     + 0 comments
    a = selecting defective
b = from plant A

p(b/a)  = p(a/b) * p(b) / p(a)

        = ((.005) * (1/7)) / ((.005*(500/3500)) + (.008*1000/3500) + (.01*2000/3500))

  • tarans97
     + 0 comments

    hey there....i exactly know how to solve this problem... the thing i don't know is test case...it is clearly given in problem that we need to find probability of selecting defective pipe from A and for that we can directly print the results without any input... i don't know what to do apart from getting that result... could anyone over here can help me out please..