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Python I multiplied every production 2 times cause in A there are 2.5 defective units, times 2 --> 5 units
from fractions import Fraction A = 500*2 pA = 0.005 defA = ['defA' for _ in range(int(A*(pA)))] B = 1000*2 pB = 0.008 defB = ['defB' for _ in range(int(B*(pB)))] C = 2000*2 pC = 0.010 defC = ['defC' for _ in range(int(C*(pC)))] totalDef = defA + defB + defC count=0 for pipe in totalDef: if pipe=='defA': count += 1 print(Fraction(count, len(totalDef)))
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Day 3: Basic Probability Puzzles #7
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Python I multiplied every production 2 times cause in A there are 2.5 defective units, times 2 --> 5 units