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Please correct the answer.
select concat(name,'('||x||')') from(
select name,substring(occupation,1,1) x from occupations);
select 'There are a total of', ab, o from(
select count(occupation) over(partition by occupation) ab,lower(occupation)||'s' o from occupations) order by ab ;
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The PADS
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Please correct the answer. select concat(name,'('||x||')') from( select name,substring(occupation,1,1) x from occupations);
select 'There are a total of', ab, o from( select count(occupation) over(partition by occupation) ab,lower(occupation)||'s' o from occupations) order by ab ;