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  1. Prepare
  2. SQL
  3. Advanced Select
  4. The PADS
  5. Discussions

The PADS

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5279 Discussions

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  • satyambhardwaj61
     + 0 comments

    select concat(name,'(',substring(occupation,1,1),')') from OCCUPATIONS order by name;

    select concat('There are a total of ',count(occupation),' ',lower(occupation),'s.') from OCCUPATIONS group by occupation order by count(occupation),occupation;

  • ksamrutha89
     + 0 comments

    Select Concat(name,'(',left(Occupation,1),')') From Occupations Order by Name Asc; Select Concat('There are a total of ',Count(Occupation),' ',Lower(Occupation),'s.') From Occupations Group by Occupation Order by Count(Occupation); This worked great

  • rishi_rt03
     + 1 comment

    Please correct the answer. select concat(name,'('||x||')') from( select name,substring(occupation,1,1) x from occupations);

    select 'There are a total of', ab, o from( select count(occupation) over(partition by occupation) ab,lower(occupation)||'s' o from occupations) order by ab ;

  • kayj6608
     + 0 comments

    SELECT CONCAT(name, '(', LEFT(occupation, 1), ')') FROM Occupations ORDER BY name;

    SELECT CONCAT('There are a total of ', COUNT(Occupation), ' ', LOWER(occupation), 's.') FROM Occupations GROUP BY Occupation ORDER BY COUNT(Occupation), LOWER(occupation);

  • faizanalvi14
     + 2 comments

    I submitted the code below and the output is perfect but still it givers error.

    SELECT CONCAT(Name, '(', SUBSTRING(Occupation, 1, 1), ')') AS Result FROM OCCUPATIONS

    UNION ALL

    SELECT CONCAT('There are a total of ', COUNT(Occupation), ' ', Occupation, 's.') AS Result FROM OCCUPATIONS GROUP BY Occupation ORDER BY Result;