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  1. Prepare
  2. SQL
  3. Advanced Select
  4. New Companies
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New Companies

  • duraidr3
     + 0 comments

    select c.company_code, c.founder,

    count(distinct l.lead_manager_code),

    count(distinct s.senior_manager_code),

    count(distinct e.manager_code),

    count(distinct e.employee_code) from Company as c

    join lead_Manager as l on c.company_code = l.company_code
    join senior_Manager as s on l.company_code = s.company_code join employee as e on s.company_code = e.company_code

    GROUP BY c.company_code, c.founder;