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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

  • Jesu_ZConte
     + 15 comments

    In Java I did this:

    public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    int n = in.nextInt();
    char [] arreglo = new char [n];
    Arrays.fill(arreglo, ' ');
    int i = 0;
    for (i = 1; i <= n; i++){
        arreglo[n-i] = '#';
        System.out.println(arreglo);
    }

}

    I hope it wasn't that bad XD but I wanted to post it cos I didn't find it that simple after all for Java. Made me think a lot. :)