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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Staircase
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Staircase

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  • byte2pixel
     + 0 comments
    for(int i = 1; i <= n; i++) {
    char[] array = [..Enumerable.Repeat(' ', n-i), ..Enumerable.Repeat('#', i)];
    Console.WriteLine(array);
}

  • awadallayossef
     + 0 comments

    time Complexity = O(n)

    def staircase(n: int):
    for x in range(1, n + 1):
        print(" " * (n - x) + "#" * x)

  • yashdeora98294
     + 0 comments

    Here is the website that published all the problems solutions - Programmingoneonone

  • tongyou1995
     + 0 comments
    def staircase(n):
    n_spaces = n - 1
    for i in range(1, n + 1):
        print(n_spaces * ' ' + i * '#')
        n_spaces -= 1
    
if __name__ == '__main__':
    n = int(input().strip())
    staircase(n)

  • devspace_fuzail
     + 0 comments

    Java 15

    public static void staircase(int n) { int repeat = 1; for(int i=n ; i > 0; i-- ) { System.out.println(" ".repeat(i-1)+"#".repeat(repeat++)); }

    }