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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

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5090 Discussions

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  • fuurkan_tuurk
     + 0 comments

    public static void staircase(int n) {

        for(int i=0;i<n;i++){
        for(int j=n-1;j>=0;j--){
            System.out.print(i<j?" ":"#");
        }
        System.out.println();
    }
}

    }

  • h120603210222
     + 0 comments
    // My code in C
void staircase(int n) {
    for(int i = 0; i < n; i++)
    {
        for(int j = n - 1 - i; j > 0; j--)
        {
            printf(" ");
        }
        for(int k = n - i - 1; k < n; k++)
        {
            printf("#");
        }
        printf("\n");
    }
    return;
}

  • alban_tyrex
     + 0 comments

    Here is my c++ implementation, you can watch the video here : https://youtu.be/4yntFcMY30U

    #include <bits/stdc++.h>

using namespace std;

int main()
{
    int n;
    cin >> n;
    for(int i = 1; i <= n; i++) {
        string s(n-i, ' '), e(i, '#');
        cout << s + e << endl;
    }

    return 0;
}

  • abisheks708
     + 0 comments

    def staircase(n): for i in range(1,n+1): print(' ' * (n - i) + '#' * i) if name == 'main': n = int(input().strip())

    staircase(n)

  • ruisanchez93
     + 0 comments

    In pyhton

       for idx in range(n):
       print((n-(idx+1))*' '+(idx+1)*'#')