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I arrived at answer in a simple way:
Say initial state of the bag is: R1 R2 R3 B1 B2 B3 B4
Imagine first marble removed is Red(R1).
The remaining is: R2 R3 B1 B2 B3 B4 = 6 marbles
Now I have to pick one more marble.
Total number outcomes = Number of permutations when I pick 1 marble from a set of 6 = P(6,1) = 6
We just want the probability of a blue marble coming in that experiment.
There are 4 possible favorable outcomes: B1,B2,B3,B4
So The probability of that outcome is = 4/6
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Day 3: Drawing Marbles
You are viewing a single comment's thread. Return to all comments →
I arrived at answer in a simple way:
Say initial state of the bag is: R1 R2 R3 B1 B2 B3 B4
Imagine first marble removed is Red(R1).
The remaining is: R2 R3 B1 B2 B3 B4 = 6 marbles
Now I have to pick one more marble.
Total number outcomes = Number of permutations when I pick 1 marble from a set of 6 = P(6,1) = 6
We just want the probability of a blue marble coming in that experiment.
There are 4 possible favorable outcomes: B1,B2,B3,B4
So The probability of that outcome is = 4/6