me too but I think yours is more clear:

from collections import OrderedDict
dct = OrderedDict()
for _ in range(int(input())):
    i = input().rpartition(" ")
    dct[i[0]] = int(i[-1]) + dct[i[0]] if i[0] in dct else int(i[-1])
for l in dct:
    print(l, dct[l])

get() works much better.

rpartition is pretty handy. thanks

You can remove one more line by doing the print in 1 line:

from collections import OrderedDict
D = OrderedDict()
for _ in range(int(input())):
    item, space, price = input().rpartition(' ')
    D[item] = D.get(item, 0) + int(price)
print(*[" ".join([item, str(price)]) for item, price in D.items()], sep="\n")

perhaps earning a variable:

item, quantity = input().rsplit(None, 1)

I did pretty much the same but I didn't know about rpartition or rsplit, so I went for this instead:

line = raw_input().split()
item, price = ' '.join(line[:-1]), int(line[-1])

Sorry, can you explain how to use d.get(item,0)?

I could not understand use of space and can item as key can have space in it. It must be right as this is working perfectly. But

plz can u explain line by line

what rpartition does here?

Thanks for rpartition, quite useful. Before it, I did:

from collections import OrderedDict

def convert(val):
    m = {
            list: lambda x: " ".join(x),
            str: lambda x: int(x)
        }
    return m[type(val)](val)

d = OrderedDict()
num_items = int(input())

for _ in range(num_items):
    *head, tail = input().split()
    item_name, item_price = map(lambda x: convert(x), [head, tail])
    d[item_name] = d.get(item_name, 0) + item_price

for k, v in d.items():
    print(k,v)

After knowing learning about it, I arrived at pretty the same solution as you.

from collections import OrderedDict

d = OrderedDict()
num_items = int(input())

for _ in range(num_items):
    item_name, _, item_price = input().rpartition(' ')
    d[item_name] = d.get(item_name, 0) + int(item_price)

for k, v in d.items():
    print(k,v)

nice :D rpartition :))

You could use rsplit with limit 1 instead of rpartition.

what d.get(item,0) does

+1 for

input().rpartition(' ')
d.get(item, 0)

Get method is pretty awesome.

Can you please explain me this. I am new to python. I am unable to fathom the operations that are being performed here on tuples and dictionaries.

In your code of OrderedDict,
Can you tell me the work of** d.get(item, 0)**

Hey, can you plz tell why it is not taking first element as " " as we have no item with 9

superb way of thinking bro

why is 'space' used?

I don't get the "space" part?

can you please explain line 5 - d[item] = d.get(item, 0) + int(quantity)

I could not get "d.get(item, 0) " part

even working without OrderedDict no need to import collections

Could you please explain what is this line of code perfoming d[item] = d.get(item, 0) + int(quantity)

I made it in 6 :

from collections import OrderedDict
dic = OrderedDict()
for _ in range(int(input())):
    item,price = input().rsplit(maxsplit=1)
    dic[item] = dic.get(item, 0) + int(price)
print(*[f'{item} {dic[item]}' for item in dic.keys()], sep='\n')

can you please explai your code @jonmcclung

Try my method by using defaultdict

**from collections import*

a=defaultdict(list)

for q in range(int(input())):

item,space,quantiy=input().rpartition(" ")

a[item].append(int(quantiy))

for w,e in a.items():

print(w,sum(e))

**

Great

can you explain line 5 ?

why have you used "space" identifier in 4th line

d[item] = d.get(item, 0) + int(quantity)

Can you explain this? Thanks in advance

what is function of odereddict in this code, can anyone explain it??

good man

can u pls explain 5th line

I tried printing d and d.items, the output looks the same but if i try to replace for item, quantity in d.items(): to for item, quantity in d: it doesn't work. Why?

Can you please explain the 5th line !

can u please explain the function of _ in for loop

This problem with Collections.OrderedDict() is instructive. I must say this is very useful for students. cheap CBD We all know the importance of maths in our education system. This section helps the students to learn maths in a very interesting way.

For this question, simple dictionary was fine. Because the items listed already in the order. OrderedDict will be usefull for other scenarios. rpartition helps me

When used rpartition and given sepererator as ' ', I know a tuple is created which also includes ' ', for instance BANANA FRIES 30, output will be ('BANANA FRIES', ' ', '30'), can someone explain why this does not appear in Ordered Dictonary?

rpartition(' ') whats this?

• from collections import OrderedDict
• d = OrderedDict()
• for _ in range(int(input())):
• item, quantity = input().rsplit(None, 1)
• d[item] = d.get(item, 0) + int(quantity)
• for item, quantity in d.items():
• print(item, quantity)

use rplit instead of rpartition. this way you don't need to save space

Thanks! it worked! But why are we using rpartition? Why can't we use just input().split for item and quantity. The next input is anway in the next line and we are already using a for loop

genius!

Thanks bro, it helped me to learn about rpartition function and get func in dictinoary!