Print the Elements of a Linked List

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    c solution


    void printLinkedList(SinglyLinkedListNode* head) { SinglyLinkedListNode* current = head;

    // Traverse the linked list and print each node's value
    while (current != NULL) {
        printf("%d\n", current->data);
        current = current->next;  // Move to the next node
    }
    

    }