Discussion on Print the Elements of a Linked List Challenge

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859 Discussions

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2 weeks ago+ 0 comments

def printLinkedList(head):
    current = head  
    while current:  
        print(current.data)
        current = current.next

3 weeks ago+ 0 comments

Here is my c++ solution, you can watch the explanation here : https://youtu.be/t3gCqS1F24w

void printLinkedList(SinglyLinkedListNode* head) {

    while(head != nullptr){
        cout << head -> data << endl;
        head = head -> next;
    }
}

1 month ago+ 0 comments

Here is my simple python solution:

def printLinkedList(head):
    print(head.data)
    if head.next is not None:
        printLinkedList(head.next)

2 months ago+ 0 comments

There is a problem to use recursion in this problem?

2 months ago+ 0 comments

Here is my c++ solution:

void printLinkedList(SinglyLinkedListNode* head) {
    for ( ; head != NULL; head = head->next)
    {
        cout << head->data << endl;
    }
}

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