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Absolute Element Sums

  • thangda
     + 0 comments

    JavaScript solution

    function playingWithNumbers(arr, queries) {
    // Write your code here
    let sum = 0;
    let other = [];
    arr.forEach(n => {
        if (n < -2000 || n > 2000) {
            sum += Math.abs(n);
        }
        else {
            other[n + 2000] = (other[n + 2000] || 0) + 1;
        }
    });
    let xx = 0;
    return queries.map(x => {
        xx += x;
        return other.reduce((acc, c, n) => acc + Math.abs(n - 2000 + xx) * c, sum);
    });
}