Discussion on Pattern Syntax Checker Challenge

2 months ago+ 0 comments

better approach rather than consuming empty line using nextLine()

public static void main(String[] args){
		Scanner in = new Scanner(System.in);
		int testCases = Integer.parseInt(in.nextLine());
		while(testCases>0 && in.hasNext()){
			String pattern = in.nextLine();
          	//Write your code
            try{
            Pattern pattern2 = Pattern.compile(pattern);
            System.out.println("Valid");
            }catch(Exception ex){
                System.out.println("Invalid");
            }
		}
        in.close();
	}

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