Discussion on Pattern Syntax Checker Challenge

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393 Discussions

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2 weeks ago+ 0 comments

Java 8

import java.util.Scanner;
import java.util.regex.*;

public class Solution
{
	public static void main(String[] args){
		Scanner in = new Scanner(System.in);
		int testCases = Integer.parseInt(in.nextLine());
		while(testCases>0){
			String pattern = in.nextLine();
          	//Write your code
            try{
                Pattern p = Pattern.compile(pattern);
                System.out.println("Valid");
            }catch(Exception e){
                System.out.println("Invalid");
            }
            testCases--;
            
		}
	}
}

4 weeks ago+ 0 comments

public static void main(String[] args){
		Scanner in = new Scanner(System.in);
		int testCases = Integer.parseInt(in.nextLine());
		while(testCases>0){
			String pattern = in.nextLine();
          	//Write your code
            try{
            Pattern pattern2 = Pattern.compile(pattern);
            System.out.println("Valid");
            }catch (PatternSyntaxException e) {  
                System.out.println("Invalid");
            }
            testCases--; 
		}
	}

1 month ago+ 0 comments

public class Solution { public static void main(String[] args){

    Scanner in = new Scanner(System.in);
    int testCases = Integer.parseInt(in.nextLine());

    while(testCases-->0){
        try {  
        Pattern.compile(in.nextLine()); 
        System.out.println("Valid");

    } catch (PatternSyntaxException e) {
        System.out.println("Invalid");
    }
    }
    in.close();
    }

}

2 months ago+ 0 comments

JAVA SOLUTION

import java.io.; import java.util.;

public class Solution { public static void pattern(String palabra){ try{ palabra.matches(palabra); System.out.println("Valid"); } catch (Exception e){ System.out.println("Invalid"); } }
public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */

    Scanner sc = new Scanner(System.in);
    int numero = sc.nextInt();
    sc.nextLine();

    for (int i = 0; i < numero; i++) {
        String palabra = sc.nextLine();            
        pattern(palabra);

    }                
}

}

2 months ago+ 0 comments

better approach rather than consuming empty line using nextLine()

public static void main(String[] args){
		Scanner in = new Scanner(System.in);
		int testCases = Integer.parseInt(in.nextLine());
		while(testCases>0 && in.hasNext()){
			String pattern = in.nextLine();
          	//Write your code
            try{
            Pattern pattern2 = Pattern.compile(pattern);
            System.out.println("Valid");
            }catch(Exception ex){
                System.out.println("Invalid");
            }
		}
        in.close();
	}

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