My java solution to convert list to arr and print arr

import java.io.; import java.math.; import java.security.; import java.text.; import java.util.; import java.util.concurrent.; import java.util.function.; import java.util.regex.; import java.util.stream.*; import static java.util.stream.Collectors.joining; import static java.util.stream.Collectors.toList;

class Result {

/*
 * Complete the 'insertionSort2' function below.
 *
 * The function accepts following parameters:
 *  1. INTEGER n
 *  2. INTEGER_ARRAY arr
 */


public static void print(int[] arr){


   for (int i : arr){

    System.out.print(i + " ");
   }
        System.out.println("");

}

// {12, 11, 7, 19, 2}
// {12, 12, 7, 19, 2}
public static void insertionSort2(int n, int[] arr) {
// Write your code here

    for (int i = 1; i < n; i++){
        int j = i -1;
        int key = arr[i];

        while ( j>= 0 && arr[j] > key){
            arr[j + 1] = arr[j];

            j--;
        }

        arr[j+1] = key;
        Result.print(arr);
    }

}

}

public class Solution { public static void main(String[] args) throws IOException { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

    int n = Integer.parseInt(bufferedReader.readLine().trim());

    int[] arr = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
        .map(Integer::parseInt).mapToInt(Integer::intValue).toArray();

    Result.insertionSort2(n, arr);

    bufferedReader.close();
}

}