In Insertion Sort Part 1, you inserted one element into an array at its correct sorted position. Using the same approach repeatedly, can you sort an entire array?
Guideline: You already can place an element into a sorted array. How can you use that code to build up a sorted array, one element at a time? Note that in the first step, when you consider an array with just the first element, it is already sorted since there's nothing to compare it to.
In this challenge, print the array after each iteration of the insertion sort, i.e., whenever the next element has been inserted at its correct position. Since the array composed of just the first element is already sorted, begin printing after placing the second element.
Example.
Working from left to right, we get the following output:
3 4 7 5 6 2 1
3 4 7 5 6 2 1
3 4 5 7 6 2 1
3 4 5 6 7 2 1
2 3 4 5 6 7 1
1 2 3 4 5 6 7
Function Description
Complete the insertionSort2 function in the editor below.
insertionSort2 has the following parameter(s):
- int n: the length of
- int arr[n]: an array of integers
Prints
At each iteration, print the array as space-separated integers on its own line.
Input Format
The first line contains an integer, , the size of .
The next line contains space-separated integers .
Constraints
Output Format
Print the entire array on a new line at every iteration.
Sample Input
STDIN Function
----- --------
6 n = 6
1 4 3 5 6 2 arr = [1, 4, 3, 5, 6, 2]
Sample Output
1 4 3 5 6 2
1 3 4 5 6 2
1 3 4 5 6 2
1 3 4 5 6 2
1 2 3 4 5 6
Explanation
Skip testing against itself at position . It is sorted.
Test position against position : , no more to check, no change.
Print
Test position against positions and :
- , new position may be . Keep checking.
- , so insert at position and move others to the right.
Print
Test position against positions (as necessary): no change.
Print
Test position against positions : no change.
Print
Test position against positions , insert at position and move others to the right.
Print