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HackerRank Language

  • kisqtya
     + 1 comment

    Python 3 solution. I was lazy to format the string into a regex :-))

    s = 'COPY THE FULL STRING FROM THE TEXT HERE, like: C:CPP...'

valid_langs = set(lang.strip() for lang in s.split(':'))

n = int(input())
for _ in range(n):
    api_id, lang = input().split(' ')
    if pow(10, 4) <= int(api_id) < pow(10, 5) and lang in valid_langs:
        print('VALID')
    else:
        print('INVALID')