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HackerRank Language

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104 Discussions

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  • preethiannjacob
     + 0 comments

    Java 15

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = Integer.parseInt(scanner.nextLine());
        String str = "C:CPP:JAVA:PYTHON:PERL:PHP:RUBY:CSHARP:"; // The full string
        ArrayList<String> arraylist = new ArrayList<String>(Arrays.asList(str.split(":")));
        Pattern pattern = Pattern.compile("\\d+\\s*(.*)");
        for(int i=0;i<n;i++)
        {   Matcher matcher = pattern.matcher(scanner.nextLine());
            if (matcher.find())
            {   if (arraylist.contains(matcher.group(1)))
                    System.out.println("VALID");
                else
                    System.out.println("INVALID");
            }
        }
    }
}

  • estevaopbsantos
     + 0 comments

    java code

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        Pattern pattern = Pattern.compile("\\d{5} (C|CPP|JAVA)"); // I couldn't put the entire string here due to the spam checker, but you get the point
        int n = Integer.parseInt(scanner.nextLine());
        for (int i = 0; i < n; i++) {
            Matcher matcher = pattern.matcher(scanner.nextLine());
            System.out.println((matcher.matches())? "VALID" : "INVALID");
        }
    }
}

  • kisqtya
     + 1 comment

    Python 3 solution. I was lazy to format the string into a regex :-))

    s = 'COPY THE FULL STRING FROM THE TEXT HERE, like: C:CPP...'

valid_langs = set(lang.strip() for lang in s.split(':'))

n = int(input())
for _ in range(n):
    api_id, lang = input().split(' ')
    if pow(10, 4) <= int(api_id) < pow(10, 5) and lang in valid_langs:
        print('VALID')
    else:
        print('INVALID')

  • avoscanemile
     + 0 comments

    Python 3

    import re
pattern = r'^\d{5}\s(C|CPP|JAVA|PYTHON|PERL|PHP|RUBY|CSHARP|HASKELL|CLOJURE|BASH|SCALA|ERLANG|CLISP|LUA|BRAINFUCK|JAVASCRIPT|GO|D|OCAML|R|PASCAL|SBCL|DART|GROOVY|OBJECTIVEC)$'
for _ in range(int(input())):
    print('VALID' if bool(re.match(pattern, input())) else "INVALID")

  • sachthemaster
     + 0 comments
    import re
s1 = "C:CPP:JAVA:PYTHON:PERL:PHP:RUBY:CSHARP:HASKELL:CLOJURE:BASH:SCALA: ERLANG:CLISP:LUA:BRAINFUCK:JAVASCRIPT:GO:D:OCAML:R:PASCAL:SBCL:DART: GROOVY:OBJECTIVEC"
sl = re.split(r'\W',s1)
sl = [i for i in sl if i!=""]

for _ in range(int(input())):
    if any(map(lambda x : x in sl, input().split())) :
        print("VALID")
    else :
        print("INVALID")