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int a,b;
void assign()
{
switch (a)
{
case 1:
printf("one\n");
break;
case 2:
printf("two\n");
break;
case 3:
printf("three\n");
break;
case 4:
printf("four\n");
break;
case 5:
printf("five\n");
break;
case 6:
printf("six\n");
break;
case 7:
printf("seven\n");
break;
case 8:
printf("eight\n");
break;
case 9:
printf("nine\n");
break;
default:
if (a > 9 && a % 2 == 0) {
printf("even\n");
}
else
{
printf("odd\n");
}
break;
}
}
int main()
{
int i = 0;
scanf("%d\n%d", &a, &b);
while ( a <= b)
{
assign();
a++;
}
return 0;
}
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For Loop in C
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////The solution without for loop
include
int a,b; void assign() {
switch (a) { case 1: printf("one\n"); break; case 2: printf("two\n"); break; case 3: printf("three\n"); break; case 4: printf("four\n"); break; case 5: printf("five\n"); break; case 6: printf("six\n"); break; case 7: printf("seven\n"); break; case 8: printf("eight\n"); break; case 9: printf("nine\n"); break; default: if (a > 9 && a % 2 == 0) { printf("even\n"); } else { printf("odd\n"); } break; } } int main() { int i = 0; scanf("%d\n%d", &a, &b); while ( a <= b) { assign(); a++; }
}