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  1. Prepare
  2. C
  3. Conditionals and Loops
  4. For Loop in C
  5. Discussions

For Loop in C

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  • galant4456
     + 0 comments
    int main() 
{
    int a, b;
    scanf("%d\n%d", &a, &b);
  	// Complete the code.
    char *arr[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    
    for (int i = a; i <= b; i++) {
        if (i <= 9)
            printf("%s\n", arr[i - 1]); 
        else {
            if (i % 2 == 0)
                printf("even\n"); 
            else
                printf("odd\n");  
        }
    }
    return 0;
}

  • srisatyachinni04
     + 0 comments

    gfvdddddddddrrrrrrrrrr

  • JoniWatkins33
     + 0 comments

    It's great for beginners to grasp the fundamental concept, and this description helps demystify the structure and flow of the for loop in programming. Well done! ekbet 40

  • Preethi_21
     + 0 comments

    int main() { int a, b; scanf("%d\n%d", &a, &b);

    char numbers[9][6] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
for (int i = a; i <= b; i++) {
    if (i <= 9)
        printf("%s\n", numbers[i - 1]); 
    else {
        if (i % 2 == 0)
            printf("even\n"); 
        else
            printf("odd\n");  
    }
}
return 0;

    }

  • gurramnikhilphi1
     + 0 comments

    char *numbers[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; for (int i = a; i <= b; i++) { if (i <= 9) printf("%s\n", numbers[i-1]);
    else if (i > 9) { char *even_or_odd = (i % 2 == 0) ? "even" : "odd"; printf("%s\n", even_or_odd);
    } }