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  1. Prepare
  2. C
  3. Conditionals and Loops
  4. For Loop in C
  5. Discussions

For Loop in C

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861 Discussions

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  • SVVBathini_w
     + 0 comments

    For C

    I wrote the code from scratch just to get more practice

    #include<stdio.h>

int main()
{
    int a, b;
    scanf("%d\n%d", &a, &b);
    
    for(int i=a; i<=b; i++)
    {
        if(i >= 1 && i <= 9)
        {
            switch(i)
            {
                case 1:
                    printf("%s\n", "one");
                    break;
                case 2:
                    printf("%s\n", "two");
                    break;
                case 3:
                    printf("%s\n", "three");
                    break;
                case 4:
                    printf("%s\n", "four");
                    break;
                case 5:
                    printf("%s\n", "five");
                    break;
                case 6:
                    printf("%s\n", "six");
                    break;
                case 7:
                    printf("%s\n", "seven");
                    break;
                case 8:
                    printf("%s\n", "eight");
                    break;
                case 9:
                    printf("%s\n", "nine");
                    break;
            }
        }
        else
        {
            if(i % 2 == 0)
                printf("%s\n", "even");
            else
                printf("%s\n", "odd");
        }
    }
    
    return 0;
}

  • aminfdy0
     + 1 comment

    That simple version and u dont need to handling every case. If u have any qs I'am Here.

    #include <stdio.h>
int main(void)
{
    int a, b;
    scanf("%d\n%d", &a ,&b);
    const char *nbword[10] = {"zero", "one", "two", "three", "four" ,"five", "six", "seven" ,"eight", "nine"};
    
    int i = a;
    while (i <= b)
    {
        if (i >= 1 && i <= 9)
            printf("%s\n", nbword[i]);
        else 
        {
            if (!(i % 2 == 0))
                printf("odd\n");
            else
                printf("even\n");
        }
        i++;
    }

    }

  • enavad07
     + 0 comments
    /*  I am sharing my solution to this challenge. Any comments are welcome, as they help me improve. Thank you. */

#include <stdio.h>

int main() {
    int a, b;
    scanf("%d\n%d", &a, &b);
    
    for (short i = a; i <= b; i++) {
        
        switch (i) {
            case 1:
                printf("one\n");
                break;
            case 2:
                printf("two\n");
                break;
            case 3:
                printf("three\n");
                break;
            case 4:
                printf("four\n");
                break;
            case 5:
                printf("five\n");
                break;
            case 6:
                printf("six\n");
                break;
            case 7:
                printf("seven\n");
                break;
            case 8:
                printf("eight\n");
                break;
            case 9:
                printf("nine\n");
                break;
            default:
                if (i % 2 == 0) {
                    printf("even\n");
                } else {
                    printf("odd\n");
                }
                break;
        }
    }

    return 0;
}

  • parkerolivia098
     + 0 comments

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  • bhanuprakashsur3
     + 0 comments

    int main() { int a, b; scanf("%d\n%d", &a, &b); for(int i =a; i 

    }
return 0;

    }