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some of the solutions refers to C,so here is to corner MBC:
import math ab=int(input()) bc=int(input()) ac=math.sqrt(ab**2+bc**2) mc=ac/2 rad_c = math.asin(ab/ac) mb=math.sqrt(bc**2+mc**2-math.cos(rad_c)*(2*bc*mc)) rad_mb=math.acos((mb**2+bc**2-mc**2)/(2*mb*bc)) print(str(round(180/math.pi*rad_mb))+chr(176))
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Find Angle MBC
You are viewing a single comment's thread. Return to all comments →
some of the solutions refers to C,so here is to corner MBC: