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  1. Prepare
  2. Python
  3. Math
  4. Find Angle MBC
  5. Discussions

Find Angle MBC

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838 Discussions

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  • theflippedbit
     + 0 comments

    Notice that AM = MC = MB (right angle triangle inscibed in a circumcirle property) once that is established, use sine rule a/sin A = b/sin B to get the desired angle.

    import math

AB = int(input())
BC = int(input())


AC = math.sqrt(AB**2 + BC**2)

theta = str(int(round(360*math.asin(AB/AC)*(1/(2*math.pi))))) + chr(176)

print(theta)

  • wazirzoh1
     + 0 comments

    import math

    a = int(input()) b = int(input())

    radies = math.atan(a/b) degrees = math.degrees(radies) round = round(degrees) e = chr(176) print(f"{round}{e}")

  • sefamutlucu
     + 0 comments
    import math

ab = int(input())
bc = int(input())

print(round(math.degrees(math.atan(ab / bc))), chr(176), sep="")

  • yvonnesunny
     + 1 comment

    some of the solutions refers to C,so here is to corner MBC:

    import math
ab=int(input())
bc=int(input())
ac=math.sqrt(ab**2+bc**2)
mc=ac/2
rad_c = math.asin(ab/ac) 
mb=math.sqrt(bc**2+mc**2-math.cos(rad_c)*(2*bc*mc))
rad_mb=math.acos((mb**2+bc**2-mc**2)/(2*mb*bc))
print(str(round(180/math.pi*rad_mb))+chr(176))

  • sanika_patil31
     + 0 comments

    Enter your code here. Read input from STDIN. Print output to STDOUT

    import math a=int(input()) b=int(input())

    c=math.degrees(math.atan2(a,b)) d=round(c) e=chr(176) print(f"{d}{e}") *