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def pageCount(n, p): no_front = p//2 if n % 2 ==0: no_back = (n-p+1)//2 else: no_back = (n-p)//2
return min(no_front, no_back)
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Drawing Book
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Please suggest for optimization
def pageCount(n, p): no_front = p//2 if n % 2 ==0: no_back = (n-p+1)//2 else: no_back = (n-p)//2