"Each page except the last page will always be printed on both sides. The last page may only be printed on the front, given the length of the book."

What does that bolded part even mean?

1->2,3->4,5->6

**o. front flips-> ** * new page starting with even number : if p is even then p/2=front flips * if p is odd then p-1/2=front flips

** o. from back ->** * if page even: n-p/2=back flips * if page is odd: n-p-1/2=back flips

Here's the solution in python:

def pageCount(n, p):
# Calculate turns from front and back
front_turns = p // 2
back_turns = (n // 2) - (p // 2)

# Return the minimum of the two
return min(front_turns, back_turns)

Here is my c++ solution, you can watch the explanation here : https://youtu.be/1T650YeAwRI

int pageCount(int n, int p) {
    return min(p/2, n/2-p/2);
}

Intuative using loop

def pageCount(n, p):
    
    # Write your code here
    start_count = 0
    end_count = 0
    start = 1
    end = n
    
    # From start
    i = 1
    while i <= end:
        
        if i >= p:
            break
        
        i = i + 2
        start_count += 1
    
    # From end
    if end % 2 == 0:
        j = end
    else:
        j = end - 1
    while j >= start:
        
        if j <= p:
            break
            
        j = j - 2
        end_count += 1
        
    return min(start_count, end_count)