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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Cats and a Mouse
  5. Discussions

Cats and a Mouse

  • dhruvbhagat98
     + 0 comments

    JS, Javascript Solution:-

    function catAndMouse(x, y, z) {
    const aMDistance = Math.abs(x-z)
    const bMDistance = Math.abs(y-z)
    if (aMDistance === bMDistance) return "Mouse C"; else if (aMDistance > bMDistance) return 'Cat B';
    return 'Cat A';
}