Discussion on Cats and a Mouse Challenge

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2 weeks ago+ 0 comments

I thought using a dictionary of exclusive boolean statements would be fun

`def catAndMouse(x, y, z):

catA_dist = abs(x-z)
catB_dist = abs(y-z)

d = {catA_dist < catB_dist:'Cat A',
     catA_dist > catB_dist:'Cat B',
     catA_dist == catB_dist:'Mouse C',
}

return d[True]

3 weeks ago+ 0 comments

Here is my c++ solution, you can watch the explanation here : https://youtu.be/vbV5-DqJU74

string catAndMouse(int x, int y, int z) {
    int a = abs(x-z), b = abs(y-z);
    if(a==b) return "Mouse C";
    if(a < b) return "Cat A";
    return "Cat B";
}

Short version

string catAndMouse(int x, int y, int z) {
    int a = abs(x-z), b = abs(y-z);
    return (a > b) ? "Cat B" : (a < b) ? "Cat A" : "Mouse C";
}

1 month ago+ 0 comments

def catAndMouse(x, y, z):
    #
    # Write your code here.
    #
    
    step1 = abs(z - x)
    step2 = abs(z - y)
    
    if step1 == step2:
        return 'Mouse C'
        
    elif step1 < step2:
        return 'Cat A'
    
    elif step2 < step1:
        return 'Cat B'

1 month ago+ 0 comments

// Complete the catAndMouse function below.

static string catAndMouse(int x, int y, int z) {

    int mouseToCatA = int.Abs(x - z);
    int mouseToCatB = int.Abs(y - z);

    if(mouseToCatA == mouseToCatB)
    {
        return "Mouse C";
    }
    else if(mouseToCatA < mouseToCatB)
    {
        return "Cat A";
    }
    else return "Cat B";

}

2 months ago+ 0 comments

Perl:

sub catAndMouse {
    my ($x, $y, $z) = @_;
    
    return "Mouse C" if (abs($y - $z) == abs($x - $z));
    return (abs($y - $z) > abs($x - $z)) ? "Cat A" : "Cat B";
}

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