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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Cats and a Mouse
  5. Discussions

Cats and a Mouse

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1254 Discussions

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  • pt023150
     + 0 comments

    java (8)

    static String catAndMouse(int x, int y, int z) {

    String result = "Mouse C";

    int catA = Math.abs(z - x);
    int catB = Math.abs(z - y);

    if (catA > catB) {
        result = "Cat B";
    }

    else if (catA < catB) {

        result = "Cat A";

    }

    return result;

}

  • alban_tyrex
     + 0 comments

    Here is my c++ solution, you can watch the explanation here : https://youtu.be/vbV5-DqJU74

    string catAndMouse(int x, int y, int z) {
    int a = abs(x-z), b = abs(y-z);
    if(a==b) return "Mouse C";
    if(a < b) return "Cat A";
    return "Cat B";
}

    Short version

    string catAndMouse(int x, int y, int z) {
    int a = abs(x-z), b = abs(y-z);
    return (a > b) ? "Cat B" : (a < b) ? "Cat A" : "Mouse C";
}

  • illogicalsleepi1
     + 0 comments
    def catAndMouse(x, y, z):
    if abs(x-z)<abs(y-z):
        return 'Cat A' 
    elif abs(x-z)>abs(y-z):
        return 'Cat B' 
    elif abs(x-z)==abs(y-z):
        return 'Mouse C'

  • nikhiltiwari2421
     + 0 comments

    if abs(x-z)==abs(y-z): return "Mouse C" elif(abs(x-z)>abs(y-z)): return "Cat B"
    else: return "Cat A"

  • sergio777leviat1
     + 0 comments

    Python solution

    def catAndMouse(x, y, z):
    if abs(z - x) < abs(z - y):
        return "Cat A"
    elif abs(z - x) > abs(z - y):
        return "Cat B"
    else:
        return "Mouse C"