public static int beautifulBinaryString(String b) {
        //goal: determine min removals to a string not have 010
        int min = 0;
        for (int i = 0; i < b.length() - 2; i++) {
            if (b.substring(i, i + 3).equals("010")) {
                min++;
                i += 2; // Skip next two characters to avoid overlapping patterns
            }
        }
        return min;
    }