def beautifulBinaryString(b):
    # Write your code here
    return len(b.split('010'))-1

int beautifulBinaryString(string b) {
    int ans = 0;
    for(int i = 0; i < b.size();){
        string sub = b.substr(i, 3);
        if(sub == "010") {
            ans++;
            i+=3;
        }else i++;
    }
    return ans;
}

int beautifulBinaryString(string b) {
    regex re("010");
    string c = regex_replace(b, re, "");
    return (b.size() - c.size()) / 3;
}

def beautifulBinaryString(b):
    # Write your code here

    count = 0   
    while b.find('010') != -1:
       b = b.replace('010', '011', 1)
       count +=1
    
    return count

sub beautifulBinaryString {
    my $b = shift;
    my $cnt = 0;

    while ($b =~ m/010/) {
        $b =~ s/010/011/;
        $cnt++;
    }
    return $cnt;
}

function beautifulBinaryString(b: string): number {
    /**
     * replace and counting until [b] doesn't include '010' any more
     */
    let count = 0

    while (b.includes('010')) {
        b = b.replace('010', '011')
        count++
    }

    return count;
}