int beautifulBinaryString(char* b) {
    int count = 0;
    int length = strlen(b);
    
    for (int i = 0; i <= length - 3; i++) {
        // Check for the substring "010"
        if (b[i] == '0' && b[i + 1] == '1' && b[i + 2] == '0') {
            count++;
            // Skip the next two characters to avoid overlapping
            i += 2; 
        }
    }
    
    return count;
}

int beautifulBinaryString(string b) {
    int ans = 0;
    for(int i = 0; i < b.size();){
        string sub = b.substr(i, 3);
        if(sub == "010") {
            ans++;
            i+=3;
        }else i++;
    }
    return ans;
}

int beautifulBinaryString(string b) {
    regex re("010");
    string c = regex_replace(b, re, "");
    return (b.size() - c.size()) / 3;
}

def beautifulBinaryString(b):
    num = 0
    while len(b)>=3:
        if b[:3] == '010':
            num += 1
            b = b[3:]
        else:
           b = b[1:]
    return num

def beautifulBinaryString(b):
    return b.count("010")