int beautifulBinaryString(char* b) {
    int count = 0;
    int length = strlen(b);
    
    for (int i = 0; i <= length - 3; i++) {
        // Check for the substring "010"
        if (b[i] == '0' && b[i + 1] == '1' && b[i + 2] == '0') {
            count++;
            // Skip the next two characters to avoid overlapping
            i += 2; 
        }
    }
    
    return count;
}