from itertools import *
import math
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
n_a=[]
n_b=[]
sa=sum(a)
sb=sum(b)
flag=0
for i in range(n):
    n_a.append(list(range(1,a[i]+1)))   """make a list of all possible values of number of bad products for each product by A"""
    n_b.append(list(range(1,b[i]+1)))    #same for B
    
for i in product(*n_a):      """iterate through all the possible combinations of number of bad product by A"""
     for j in product(*n_b):  """iterate through all the possible combinations of number of bad product by B"""
           count=0                """counting the number of times ratio is maintained for the current combination number of bad products by A and B """
           p=sum(i)*sb            """expression you will get by putting the given condition in a equation (A-overall/B-overall) spoilage ratio"""
           q=sum(j)*sa
           m=math.gcd(p,q)  """reduce the fraction to its lowest terms"""
           p,q=p//m,q//m          
 
           if (p/q)<=1:           """less than 1 then continue to next iteration"""
                  continue

           for k in range(n):     """each pair of kth product check the equality of ratio """
                  r=(j[k]*a[k])
                  s=(i[k]*b[k])         """expression you will get by putting the given condition in a equation (B-kth/A-kth) per product spoilage ratio"""
                  
                  t=math.gcd(r,s)      """reduce the fraction to its lowest terms"""
                  r,s=r//t,s//t

                   if r!=p or s!=q :     """not equal then break the loop and go for next combination of i and j (change j)"""
                             break
                   else:
                              count+=1          """equal then increase count"""
             
                   if count==n:          """the ratio is same for all the n products then print the ratio and exit all the loops"""
                               flag=1
                               print("{}/{}".format(r,s))
                               break

           if flag==1:
                 break

    if flag==1:
        break