Project Euler #230: Fibonacci Words

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    I could not test perfectly, but using my test data it is OK! If someone has test case's please share it to test! Thank You!

    #define ULLINT  unsigned long long int
    int main() {
        ULLINT fibt[93] = { 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, 832040, 1346269, 2178309, 3524578, 5702887, 9227465, 14930352, 24157817, 39088169, 63245986, 102334155, 165580141, 267914296, 433494437, 701408733, 1134903170, 1836311903, 2971215073, 4807526976, 7778742049, 12586269025, 20365011074, 32951280099, 53316291173, 86267571272, 139583862445, 225851433717, 365435296162, 591286729879, 956722026041, 1548008755920, 2504730781961, 4052739537881, 6557470319842, 10610209857723, 17167680177565, 27777890035288, 44945570212853, 72723460248141, 117669030460994, 190392490709135, 308061521170129, 498454011879264, 806515533049393, 1304969544928657, 2111485077978050, 3416454622906707, 5527939700884757, 8944394323791464, 14472334024676221, 23416728348467685, 37889062373143906, 61305790721611591, 99194853094755497, 160500643816367088, 259695496911122585, 420196140727489673, 679891637638612258, 1100087778366101931, 1779979416004714189, 2880067194370816120, 4660046610375530309, 7540113804746346429, 12200160415121876738 };    
        
        int db;
        cin >> db;
        for( int idb=0 ; idb < db; idb++ ) {
            string A, B;
            long n;
            cin >> A >> B;
            cin >> n;
    
            int itemh = A.length();
    
            ULLINT k = n;
            ULLINT i = 2;
            ULLINT mintah = fibt[i] * itemh;
            while( k >= mintah ) {
                i++;
                mintah = fibt[i] * itemh;
            }
    
            do{
                mintah = fibt[i-2] * itemh;
                if( mintah < k ) {
                        mintah = fibt[i-2] * itemh;
                        k -= mintah;
                } else {
                        i--;
                }
                i--;
            }
            while( i > 1 );
    
            if( k > 0 ) k--;
    
            if( i == 0 )
                cout << A.substr( k, 1 ) << endl;
            else
                cout << B.substr( k, 1 ) << endl;
    
    }
    
    return 0;
    

    }