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Please find my unique solution. Requesting comment on this context for all.
1) (3*3)-(2*2)-(1*1)=4 ; 2) (8*8)-(6*6)-(4*4)=12; 3) (5*5)-(3*3)-(1*1)=15; 4) (6*6)-(4*4)-(2*2)=16; 5) (13*13)-(10*10)-(7*7)=20; 6) (12*12)-(9*9)-(6*6)=27; 7) (18*18)-(14*14)-(10*10)=28; 8) (7*7)-(4*4)-(1*1)=32; 9) (8*8)-(5*5)-(2*2)=35; 10) (9*9)-(6*6)-(3*3)=36; 11) (17*17)-(13*13)-(9*9)=39; 12) (28*28)-(22*22)-(16*16)=44; 13) (16*16)-(12*12)-(8*8)=48; 14) (22*22)-(17*17)-(12*12)=51; 15) (33*33)-(26*26)-(19*19)=52; 16) (9*9)-(5*5)-(1*1)=55; 17) (10*10)-(6*6)-(2*2)=60; 18) (11*11)-(7*7)-(3*3)=63; 19) (12*12)-(8*8)-(4*4)=64; 20) (43*43)-(34*34)-(25*25)=68; 21) (20*20)-(15*15)-(10*10)=75; 22) (48*48)-(38*38)-(28*28)=76; 23) (26*26)-(20*20)-(14*14)=80; 24) (11*11)-(6*6)-(1*1)=84; 25) (37*37)-(29*29)-(21*21)=87; 26) (12*12)-(7*7)-(2*2)=91; 27) (58*58)-(46*46)-(34*34)=92; 28) (25*25)-(19*19)-(13*13)=95; 29) (13*13)-(8*8)-(3*3)=96; 30) (14*14)-(9*9)-(4*4)=99;
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Project Euler #136: Singleton difference
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Please find my unique solution. Requesting comment on this context for all.
1) (3*3)-(2*2)-(1*1)=4 ;
2) (8*8)-(6*6)-(4*4)=12;
3) (5*5)-(3*3)-(1*1)=15;
4) (6*6)-(4*4)-(2*2)=16;
5) (13*13)-(10*10)-(7*7)=20;
6) (12*12)-(9*9)-(6*6)=27;
7) (18*18)-(14*14)-(10*10)=28;
8) (7*7)-(4*4)-(1*1)=32;
9) (8*8)-(5*5)-(2*2)=35;
10) (9*9)-(6*6)-(3*3)=36;
11) (17*17)-(13*13)-(9*9)=39;
12) (28*28)-(22*22)-(16*16)=44;
13) (16*16)-(12*12)-(8*8)=48;
14) (22*22)-(17*17)-(12*12)=51;
15) (33*33)-(26*26)-(19*19)=52;
16) (9*9)-(5*5)-(1*1)=55;
17) (10*10)-(6*6)-(2*2)=60;
18) (11*11)-(7*7)-(3*3)=63;
19) (12*12)-(8*8)-(4*4)=64;
20) (43*43)-(34*34)-(25*25)=68;
21) (20*20)-(15*15)-(10*10)=75;
22) (48*48)-(38*38)-(28*28)=76;
23) (26*26)-(20*20)-(14*14)=80;
24) (11*11)-(6*6)-(1*1)=84;
25) (37*37)-(29*29)-(21*21)=87;
26) (12*12)-(7*7)-(2*2)=91;
27) (58*58)-(46*46)-(34*34)=92;
28) (25*25)-(19*19)-(13*13)=95;
29) (13*13)-(8*8)-(3*3)=96;
30) (14*14)-(9*9)-(4*4)=99;