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import math def C(n,r): f = math.factorial return f(n) // f(r) // f(n-r) t=int(input()) for i in range(t): n=int(input()) r=g=b=0 for rr in range(1,(n//2)+1): r+=C(n-rr,rr) for gg in range(1,(n//3)+1): g+=C(n-(2*gg),gg) for bb in range(1,(n//4)+1): b+=C(n-(3*bb),bb) print((r+g+b)%1000000007)
I think it take less time with compare to next (;一_一) but nope, it's take 8.33% more loop than 0-n
for i in range(int(input())): a=b=m=n=o=w=x=y=z=1 for j in range(1,int(input())): a,b,m,n,o,w,x,y,z = b,a+b,n,o,o+m,x,y,z,z+w print((b+n+x-3)%1000000007)
smallest in size (lines of code)?
but still TLE ಠ_ಥ
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Project Euler #116: Red, green or blue tiles
You are viewing a single comment's thread. Return to all comments →
I think it take less time with compare to next (;一_一) but nope, it's take 8.33% more loop than 0-n
smallest in size (lines of code)?
but still TLE ಠ_ಥ