Project Euler #110: Diophantine reciprocals II

  • + 2 comments

    can u add more information which help me to understand the issue

    • Asked to answer
      + 1 comment

      You should find all x,y that verify the given equation and give the number of the solution just note that (x,y) and (y,x) are considered one solution. Start first by finding the writing of X and Y using arithmetics

      • + 1 comment

        As per Algo description, n=1260 than we will have 113 distinct solution, what are those value of solution and what are x and y value which cover 113 possiblity. need small example if possible

        • + 0 comments

          these are some example for n=8 we should find all x,y that verify x*y/(x+y)=8 And we get (9,8*9) (2*6,4*6) (4*6,2*6) (8*9,9 ) (2*5,8*5) (4*4,4*4) (8*5,2*5) (4*3,8*3) (8*3,4*3) (8*2,8*2) By removing none distinct We get (9,8*9) (2*6,4*6) (2*5,8*5) (4*4,4*4) try to find x,y using arithmetic

    • + 1 comment

      1/1261+1/1588860,1/1262+1/795060,1/1263+1/530460,1/1264+1/398160,1/1265+1/318780,1/1266+1/265860,1/1267+1/228060,1/1269+1/177660,1/1270+1/160020,1/1272+1/133560,1/1274+1/114660,1/1275+1/107100,1/1278+1/89460,1/1280+1/80640,1/1281+1/76860,1/1288+1/57960,1/1290+1/54180,1/1295+1/46620,1/1296+1/45360,1/1302+1/39060,1/1305+1/36540,1/1320+1/27720,1/1323+1/26460,1/1330+1/23940,1/1344+1/20160,1/1350+1/18900,1/1365+1/16380,1/1386+1/13860,1/1400+1/12600,1/1440+1/10080,1/1470+1/8820,1/1512+1/7560,1/1575+1/6300,1/1680+1/5040,1/1890+1/3780,1/2520+1/2520. Ok, they are actually only 36 !?

      • + 0 comments

        try solving Diophantine reciprocals I,you'll find that there are 113 solution for 1260. NB: 36 is only the number of multiples of 1260. If you apply the same logic to 8 you wont find the solutions i gave above