import itertools
def list_adder(strings,number):
    '''Create all possible strings with number added at all indices in string in strings'''
    l=len(strings[0])+1 #+1, because I also have to add number at last position 
    lis=[string[:i]+str(number)+string[i:] for string in strings for i in range(l)]
    return lis

def permuter(lis1,lis2):
    '''It creates all possible permutations with lis1 as unordered and lis2 as ordered'''
    while lis1:
        n=lis1.pop()
        lis2=list_adder(lis2,n)
    return set(lis2)

def lis_to_str(list1):
    '''Take in a sequence of numbers and returns a str of them'''
    return ''.join([str(no) for no in list1])

def lis_to_int(list1):
    '''Take in a sequence of numbers and return int formed by combining them'''
    return int(''.join([str(no) for no in list1]))

item=input().split()
n=int(item[0])
k=int(item[1])

li1=list(itertools.combinations_with_replacement(range(1,10),r=k)) #This is the list of possible combinations of numbers which are common in numerator and denominator

li2=list(itertools.product(range(10),repeat=n-k)) #The ordered combinations of other digits in numerator or denominator
li2.remove((0,)*(n-k)) # after cancelling common digits we should'nt be left with something like 00/00 or 00/12 etc

answers=set() #so that I don't count repeated fractions
li3=[] # it contains for a particular element in li all the possible casses of elements in li2 with the numerator or denominator as in the format (12,1234) all stored in a list
for i in li1:
    li4=[]
    for j in li2:
        li4+=[(lis_to_int(j),int(i)) for i in permuter(list(i),[lis_to_str(j)]) if i[0]!='0'] # we should'nt get number like 0123 for n=4
    li3.append(li4)

for i in li3:
    for item in itertools.combinations(i,r=2): # I just used combinations instead of permutations cause the left over numerator should be less than left over denominator and the storing order was lexicographical
        if item[0][0]<item[1][0] and item[0][0]*item[1][1]==item[1][0]*item[0][1]:
            answers.add((item[0][1],item[1][1]))

print(sum([a[0] for a in answers]), sum([a[1] for a in answers]))