import java.io.; import java.util.;

public class Solution {

public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */

    Scanner scanner = new Scanner(System.in);
    int n = scanner.nextInt(); // Read the input

    long sum = 0; // Variable to store the sum

    for (int i = 10; i <= 999999; i++) { 
        if (isDigitPowerSum(i, n)) { 
            sum += i; 
        }
    }

    System.out.println(sum);
}
public static boolean isDigitPowerSum(int num, int n) {

    int sum = 0 ;
    int orignal= num;
    while(num>0){
        int digit = num % 10;
        sum += Math.pow(digit, n);
        num /= 10;
    }
    return sum==orignal;

}

}

//C# using System;

class Program { static int PowerSum(int num, int power) { int sum = 0; int temp = num;

    while (temp > 0)
    {
        int digit = temp % 10;
        sum += (int)Math.Pow(digit, power);
        temp /= 10;
    }

    return sum;
}

static void Main()
{
    int N = int.Parse(Console.ReadLine());
    int totalSum = 0;

    for (int i = 10; i <= 999999; i++)
    {
        if (i == PowerSum(i, N))
        {
            totalSum += i;
        }
    }

    Console.WriteLine(totalSum);
}

}

This code workes well using python 3

def main():
    n = int(input())
    total_sum = 0

    for i in range(2, 10**6):
        temp = i
        sum1 = 0

        while temp > 0:
            a = temp % 10
            sum1 += a**n
            temp = temp // 10

        if sum1 == i:
            total_sum += sum1

    print(total_sum)

if __name__ == "__main__":
    main()

for n=5, it also has numbers ranging from 1000 to 1000000, so the solution in python will be

n=int(input().strip()) sum_=0 if n==5: sum_ = sum([i for i in range(10**(n-2), 10**(n+1)) if sum(int(digit)n for digit in str(i)) == i]) print(sum_) else: sum_ = sum([i for i in range(10(n-1), 10**(n)) if sum(int(digit)**n for digit in str(i)) == i]) print(sum_)