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Project Euler #6: Sum square difference
Project Euler #6: Sum square difference
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100% python
import re import sys
def difference(number1 , number2): return number1 - number2
List = []
if name == 'main': t = int(input().strip())
I solved this question mathematically: (3n^4 + 2n^3 - 3n^2 - 2n) / 12
!/bin/python3
import sys
t = int(input().strip()) for a0 in range(t): n = int(input().strip()) s1=0 s2=0 for i in range(1,n+1): s1+=i s2+=i**2 sum=s1**2-s2 print(sum)