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public static int largestPrimeDivisor(long n) {
int largestPrime = -1;
while (n % 2 == 0) {
largestPrime = 2;
n /= 2;
}
for (int i = 3; i * i <= n; i += 2) {
while (n % i == 0) {
largestPrime = i;
n /= i; // Remove the factor i from n
}
}
if (n > 1) {
largestPrime = (int) n;
}
return largestPrime;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int t = in.nextInt();
for (int testCaseIndex = 0; testCaseIndex < t; testCaseIndex++) {
long n = in.nextLong();
int result = largestPrimeDivisor(n);
System.out.println(result);
}
in.close();
}
}
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Project Euler #3: Largest prime factor
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can anyone make my code more optimized
import java.io.; import java.util.;
public class Solution {
}