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Project Euler #1: Multiples of 3 and 5
Project Euler #1: Multiples of 3 and 5
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import Control.Applicative import Control.Monad import System.IO
sumTo :: Integer -> Integer sumTo 0 = 0 sumTo n = (n * (n + 1))
div
2multSum :: Integer -> Integer multSum 0 = 0; multSum n = total_sum where three_max = n
div
3; five_max = ndiv
5; fifteen_max = ndiv
15; three_mult = 3 * (sumTo three_max); five_mult = 5 * (sumTo five_max); fifteen_mult = 15 * (sumTo fifteen_max); total_sum = three_mult + five_mult - fifteen_multmain :: IO () main = do t_temp <- getLine let t = read t_temp :: Int forM_ [1..t] $ \a0 -> do n_temp <- getLine let n = read n_temp :: Integer let sum = multSum (n - 1) print (sum)
for(int a0 = 0; a0 < t; a0++){ int n = in.nextInt(); System.out.println(sumOfMultiples(n-1)); }}
private static long sumOfMultiples(int n) { return sumDivisibleBy(n, 3) + sumDivisibleBy(n, 5) - sumDivisibleBy(n, 15); } private static long sumDivisibleBy(int n, int k) { int p = n / k; return k * (long)p * (p + 1) / 2; } }
Python, this is my sarcasticly built one line... But I keep getting a timeout on two of the tests. Tried basic for loop, itterating a value, sum a list, writing it all out line by line... [print(sum(map(lambda x: x if x % 3 ==0 or x % 5 == 0 else 0, range(3, int(input()))))) for _ in range(int(input()))]
int main(){ int t; cin >> t; for(int a0 = 0; a0 < t; a0++){ int n; cin >> n; long long sum=0;
Haskell