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  3. Constructing a Number
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Constructing a Number

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33 Discussions

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  • sufiyankallada
     + 0 comments

    python 3

    def canConstruct(a):

    sum1=0
for i in a:
    sum1+=i%3
if(sum1%3==0):
    print("Yes")
else:
    print("No")

    if name == 'main':

    t = int(input().strip())

for t_itr in range(t):
    n = int(input().strip())

    a = list(map(int, input().split()))

    canConstruct(a)

  • gourav1998chotu
     + 0 comments

    My solution for this code is.

    public static String canConstruct(List<Integer> a) {
    // Return "Yes" or "No" denoting whether you can construct the required number.
       int sum=0;
        int[] arr=a.stream().mapToInt(Integer::intValue).toArray();

        for(int l:arr){
            sum+=l;
        }
        if(sum%3==0)
            return "Yes";
        }

       return "No";
         }

  • seenimadhavan2
     + 0 comments

    \Answer for this// char* canConstruct(int a_count, int* a) { // Return "Yes" or "No" denoting whether you can construct the required number. static char str1[]="Yes"; static char str2[]="No"; long int s=0,i; for(i=0;i

  • sarkermt
     + 0 comments
    static String canConstruct(int[] a) {
        // Return "Yes" or "No" denoting whether you can construct the required number.
        long sum = 0;
        for(int i:a){
            sum+=i;
        }

        return sum%3==0? "Yes":"No";
    }

  • abhilash97sharma
     + 0 comments

    static String canConstruct(int[] a) { // Return "Yes" or "No" denoting whether you can construct the required number. int len=a.length; int sum=0; for(int a1:a){ for(;a1>0;a1=a1/10) sum=sum+a1%10; } if(sum%3==0) return "Yes"; else return "No"; }