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int range = (b-a)+1; int limit = (range-x)+1; int[] arr = new int[x]; int start=a; for(int i=0;i<limit;i++){ int inside = start; for(int j=0;j<x;j++){ arr[j] = inside; inside++; } int check = arr[0]*2; if(arr[x-1]>=check && arr.length==range ){ int ans = -1; System.out.print(ans); break; }else if(arr[x-1]<check){ for(int k=0;k<x;k++){ System.out.print(arr[k]+" "); } System.out.println(""); break; } start++; }
Why set [3,4,5] is not accepted as avalid output when it was clearly mentioned it is also one of the valid output in explanation.
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Mutual Indivisibility
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Why set [3,4,5] is not accepted as avalid output when it was clearly mentioned it is also one of the valid output in explanation.