This is my solution

 // Complete the repeatedString function below.

static long repeatedString(String s, long n) {
long len= Long.valueOf(s.length());
    int a=0;
    for (int i = 0; i < len; i++) {
        if (s.charAt(i) == 'a') 
            ++a;
    }
     long occ = (n/len) * a;
    for (int i = 0; i < n%len; i++) {
        if (s.charAt(i) == 'a')
            ++occ;
    }
    return occ;
}

This is my solution

package hackerrankcode;

import java.io.; import java.math.BigInteger; import java.util.;

public class Repeated_String {

public static BigInteger repeat(String s,long n){

    BigInteger min = new BigInteger("9223372036854775808");

    BigInteger increment = new BigInteger("1");

    List<Character> list=new ArrayList<>();

    for(long i=0;i<s.length();i++){

        list.add(s.charAt((int)i));

    }

    //System.out.println("The list is: "+list);

    if(list.contains("a")){

       // System.out.println("output from here");

        BigInteger bigInteger=new BigInteger("0");

        return bigInteger;

    }else if(n>=list.size() && n<=Math.pow(10, 6)){

        int y=0;

        while(list.size()!=n){

            list.add(s.charAt(y));

            y++;

            if(y==s.length()){

                y=0;

            }

        }

    }else{

    BigInteger a = min.add(increment);    

        BigInteger bigInteger=new BigInteger(String.valueOf(n));

      //  System.out.println("Output from else");

        return a;

    }
     int a=0;

     //System.out.println("The list2 is: "+list);

    for(Character i:list){

        if(i=='a'){

            a++;

        }

    }

    BigInteger bigInteger=new BigInteger(String.valueOf(a));

    return bigInteger;

}

public static void main(String[] args) {

Scanner scanner=new Scanner(System.in);    

String repeatedString;
long n;

    System.out.println("Enter your string: ");
    repeatedString=scanner.nextLine();

    System.out.println("Enter your number: ");
    n=scanner.nextLong();

    System.out.println(""+String.valueOf(repeat(repeatedString,n)));

}}

}

//}

this is my solution

public static void main(String[] args) { Scanner in = new Scanner(System.in); String s = in.next(); long n = in.nextLong();

    long numOfChar = 0 ;
    int numOfA = 0;
    int stringLength = s.length();

    if(stringLength > 0){
       for(int i=0;i<stringLength;i++){
          if(s.charAt(i)=='a'){
            numOfA++;
          } 
       } 

       long division = n / stringLength;
       long mod = n % stringLength;
       numOfChar = division * numOfA;

       for(int i=0;i<mod;i++){
           if(s.charAt(i)=='a'){
               numOfChar++;
           }
       }

    }

    System.out.println(numOfChar);
}

l = len(s) if(l==1 and s=='a'): print(n) else: c = s.count('a') c *= n//l s = s[:(n%l)] c+=s.count('a') print(c)

!/bin/python3

import sys

s = input().strip() n = int(input().strip()) c=s.count('a') f=int(n/len(s)) r=n%len(s) print(c*f+s[0:r].count('a'))