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  1. Prepare
  2. Algorithms
  3. Debugging
  4. Zig Zag Sequence
  5. Discussions

Zig Zag Sequence

  • rachel70
     + 2 comments

    I am not sure how to make this 3 lines or less in JS and there is no findZigZagSequence function to debug, but here's my solution (which isn't passing despite the output matching what is expected 🤔) I feel like this is fairly sloppy though.

    function processData(input) {
    const modifiedInput = input.split('\n')
    const middlePosition = Math.floor(modifiedInput[1] / 2)
    const sortedArr = modifiedInput[2].split(' ').sort((a,b) => a-b)
    const middleNumber = sortedArr.pop()
    const resultingArray = []
    for (let a = 0; a < middlePosition; a++) {
        resultingArray.push(sortedArr[a])
    }
    const reversedArray = sortedArr.reverse()
    resultingArray.push(middleNumber)
    for (let a = 0; a < middlePosition; a++) {
        resultingArray.push(reversedArray[a])
    }
    console.log(resultingArray.join(' '))
    return resultingArray.join(' ')
} 
`