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  1. Prepare
  2. Python
  3. Introduction
  4. Write a function
  5. Discussions

Write a function

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3051 Discussions

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  • krishankantshas1
     + 0 comments
    def is_leap(year):
    leap = False
    
    # Write your logic here
    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
        leap = True
    
    return leap


year = int(input())
print(is_leap(year))

  • shivamjain1712
     + 0 comments

    This is correct code and it can also pass the hidden test

    def is_leap(year):
    leap = False
    if(year%400==0):
        return True
    elif(year%100==0):
        return False
    elif(year%4==0):
        return True
    else:
        return False
    return leap

year = int(input())
print(is_leap(year))

  • bansal_gautam87
     + 0 comments

    As per the requirement I've created a function and satisfy the possible condition that question mention but I'm confused in this part (This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.) Here we need to apply some condition

    def is_leap(year): return (year % 400 == 0) or (year % 4 == 0 and year % 100 != 0)

    year = int(input()) print(is_leap(year))

  • caroll_cca_cc
     + 0 comments

    def is_leap(year): leap = False

    # Write your logic here
if year%400==0:
    leap = True
elif year%100==0:
    leap = False
elif year%4==0:
    leap = True


return leap

  • caroll_cca_cc
     + 0 comments

    def is_leap(year): leap = False

    # Write your logic here
if year%400==0:
    leap = True
elif year%100==0:
    leap = False
elif year%4==0:
    leap = True


return leap