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Words Score

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162 Discussions

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  • luca_h94
     + 0 comments
    i, words = input(), input()

def score_words(words):
    vowels=["a","e","i","o","u","y"]
    words = words.split()
    score = 0
    for word in words:
        vowelcount = 0
        for char in word:
            if char in vowels:
                vowelcount +=1
        if vowelcount % 2 == 0:
            score += 2
        else:
            score += 1 
    print(score)

score_words(words)

  • arohi_agrawal111
     + 0 comments

    Just the ++score has to be converted into score += 1. Rest of the code stays as it is.

    def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
    return score


n = int(input())
words = input().split()
print(score_words(words))

  • loucifsk
     + 1 comment

    With the use of regex and list comprehension -->

    text = sys.stdin.read().splitlines()[1].split(' ')
vowels = 'aeiouy'
score = 0

for word in text:
    if len(re.findall(rf"[{vowels}]", word, flags=re.I))%2 == 0:
        score += 2
        continue
    score +=1

print(score)

  • datyadade
     + 1 comment

    As we all know that vowels are a,e,i,o,u and why it has metioned y in the above one.

  • rejin_gunasekar1
     + 0 comments
    def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']
def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
    return score

n = int(input())
words = input().split()
print(score_words(words))