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  4. Words Score
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Words Score

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158 Discussions

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  • rejin_gunasekar1
     + 0 comments
    def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']
def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
    return score

n = int(input())
words = input().split()
print(score_words(words))

  • sunilpolimera69
     + 0 comments

    import sys

    def score_words(words): vowels = {'a','e','i','o','u','y'} score = 0 for word in words: vowels_count = sum(1 for i in word if i in vowels) if vowels_count%2==0: score = score+2 else: score = score+1 return score

    if name == "main": n = int(input()) word = input().split() words = [] for i in range(n): if len(word[i])<=20 and word[i].islower(): words.append(word[i]) print(score_words(words))

  • davindewanto
     + 0 comments
    import re

N = int(input())
score = 0
for i in input().split():
    if(len(re.findall(r"[aeiouy]", i)) %2 == 0):
        score += 2
    else:
        score += 1

print(score)

  • huzaifakhan1731
     + 0 comments

    just update the ++score to score += 1, because python does not supports the pre and post increment concepts.

  • n4m774r_d
     + 0 comments

    Seriously ... 30 points for spotting ++score .

    Ps:

    def has_vowel(letters):
    v_sum =sum([['a', 'e', 'i', 'o', 'u', 'y'].count(l) for l in letters]) 
    return  2 if  v_sum %2 == 0 else 1    
def score_words(words):
    return sum([has_vowel(w) for w in [[*map(str,word)] for word in words]])