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  1. Prepare
  2. Python
  3. Collections
  4. Word Order
  5. Discussions

Word Order

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1662 Discussions

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  • apavaloaiestefa1
     + 0 comments

    cool solution using Counter

    from collections import Counter
n = int(input())
words = [input() for _ in range(n)]
c = Counter(words)
print(len(c))
print(*c.values())

  • tiwarirahul479
     + 0 comments

    One more version:-

    n = int(input())
word_list = [input() for i in range(n)]

word_dict = {}

for word in word_list:
    if word_dict.get(word):
        word_dict[word] += 1
    else:
        word_dict[word] = 1

print(len(word_dict.keys()))
vals = list(word_dict.values())
final_vals = list(map(str, vals))
print(" ".join(final_vals))

  • guchhaitpralay7
     + 0 comments
    from collections import defaultdict

num_words = int(input())

word_frequency: defaultdict[str, int] = defaultdict(int)

for _ in range(num_words):
    word = input().strip()
    word_frequency[word] += 1

print(len(word_frequency))

for word in word_frequency:
    print(word_frequency[word], end=" ")

  • guchhaitpralay7
     + 0 comments
    from collections import defaultdict

num_words = int(input())

word_frequency: defaultdict[str, int] = defaultdict(int)

for _ in range(num_words):
    word = input().strip()
    word_frequency[word] += 1

print(len(word_frequency))

for word in word_frequency:
    print(word_frequency[word], end=" ")

  • ojaskatyal
     + 0 comments
    from collections import OrderedDict

input_dict = OrderedDict()

for _ in range(int(input())):
    word = input()
    try:
        input_dict[word] += 1
    except KeyError:
        input_dict[word] = 1

print(len(input_dict))
for val in input_dict.values():
    print(val, end = " ")