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  1. Prepare
  2. Python
  3. Collections
  4. Word Order
  5. Discussions

Word Order

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1622 Discussions

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  • f9b6uo91i
     + 0 comments

    Tried this but it is too slow, it failed two tests due to timeout. Any suggestions on what is the bottleneck and how to speed it up?

    n_words = int(input())

word_list = []
occurrence_list = []

for i in range(n_words):

    word = input()

try:
    idx = word_list.index(word)
    occurrence_list[idx] += 1
except:
    word_list.append(word)
    occurrence_list.append(1)

    print(len(word_list)) print(' '.join(map(str, occurrence_list)))

  • ahmed_gh_soliman
     + 0 comments
    from collections import Counter
n= int(input())
words= Counter([input() for _ in range(n)])
print(len(words.keys()))
print(*words.values())

  • did_padman
     + 0 comments
    n = int(input())

dic = {}

for _ in range(n):
    word = input()
    if word in dic.keys():
        dic[word]+=1
    else:
        dic[word] = 1

print(len(dic.keys()))

occ = [str(i) for i in dic.values()]

print(' '.join(occ))

  • bbquoe
     + 0 comments

    from collections import Counter

    n = int(input()) cnt = Counter()

    for _ in range(n): cnt[input()] += 1

    print(len(cnt)) print(*[cnt[i] for i in cnt])

  • ss3225220
     + 0 comments
    N = int(input())
dicts = {}
orders = []

for _ in range(N):
    orders.append(str(input()))
    
    if orders[_] not in dicts:
        dicts[orders[_]] = 1
    else:
        dicts[orders[_]] += 1
        
print(len(set(orders)))

print(" ".join(map(str, dicts.values())))

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