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  1. Prepare
  2. Python
  3. Collections
  4. Word Order
  5. Discussions

Word Order

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1636 Discussions

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  • rogerhurwitz
     + 0 comments
    from collections import Counter

n = int(input())
words = [input() for _ in range(n)]
counts = Counter(words)

print(len(counts))
for count in counts.values():
    print(count, end=" ")

  • navanilgh557
     + 0 comments

    no modules required

    n=int(input()) d={} for i in range(n): w=input() if w in d.keys(): d[w]+=1 else: d[w]=1 print(len(d)) for i in d.keys(): print(d[i],end=' ') print()

  • rohitambasta_ii1
     + 0 comments

    With Counter in Collection Module:

    from collections import Counter

n= int(input())
inp= [input() for _ in range(n)]
counter_word = Counter(inp)

key = len([key for key in counter_word.keys()])
value = " " .join([str(value) for value in counter_word.values()])
print(key)
print(value)

    Without Counter in Collection module (Conventional Approach):

    n= int(input())
inp= [input() for _ in range(n)]

inp_unique= []
count_all = []

for i in inp:
    count= 1
    if i not in inp_unique:
        inp_unique.append(i)
        count_all.append(count)           
    else:
        inp_unique.index(i)
        count_all[inp_unique.index(i)] = count_all[inp_unique.index(i)] + 1

print(len(inp_unique))
print(" ".join((map(str, count_all))))

  • thinhnoob0859
     + 0 comments

    from collections import Counter N = int(input()) D = [] for i in range(N): D.append(input()) print(len(set(D))) print(*Counter(D).values())

  • shruti_kapse06
     + 0 comments
    from collections import OrderedDict

n = int(input())
count = 0
inp_dict = OrderedDict()

for i in range(n):
    word = str(input())
    
    if word in inp_dict:
       inp_dict[word] += 1
    else:
        inp_dict[word] = 1
        count +=1
        
print(count)
print(*(inp_dict[word] for word in inp_dict))