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  1. Prepare
  2. Algorithms
  3. Strings
  4. Weighted Uniform Strings
  5. Discussions

Weighted Uniform Strings

  • ivalex01
     + 0 comments

    simple O(N) solution in Python:

    def weightedUniformStrings(s, queries):
    # Write your code here
    weights = set()
    for i, c in  enumerate(s):
        u = ord(c) - ord('a') + 1
        if i > 0 and c == s[i-1]:
            w += u
        else:
            w = u
        if w not in weights:
            weights.add(w)
    result = []       
    for q in queries:
        if q in weights:
            result.append("Yes")
        else: 
            result.append("No")
    return result