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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Validating UID
  5. Discussions

Validating UID

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535 Discussions

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  • pub_ashishk28
     + 0 comments

    python3

    import re
t = int(input())

# this relies on greedy nature of positive and negative lookahead
reg = re.compile(r'''
    (?=.*[A-Z].*[A-Z].*)     # at least two uppercase alphabets
    (?=.*[0-9].*[0-9].*[0-9].*) # at least three digits
    (?=\w{10})          # only ten alphanumeric characters in total
    (?!.*(.).*\1.*)         # no repetition of the same characters
    ''', re.VERBOSE)

for i in range(t):
    if reg.match(input().strip()):
        print("Valid")
    else:
        print("Invalid")

  • vaibhavthetiger1
     + 0 comments

    number = int(input())

    for _ in range(number): UID = input() UID_list = list(UID)

    upper_count = 0
digit_count = 0   
duplicate = False
lower_flag = False

UID_dic = dict.fromkeys(UID_list,0) 

for i in UID_list:
    if UID.isalnum() and len(UID) == 10 :     
            if i.isupper():
                upper_count = upper_count+1   
                UID_dic[i] = UID_dic[i] +1
            if i in ["0","1","2","3","4","5","6","7","8","9"]:
                digit_count = digit_count+1
                UID_dic[i] = UID_dic[i] +1
            if i.islower():
                lower_flag = True
                UID_dic[i] = UID_dic[i] +1

for i in UID_list:
    if UID_dic[i] > 1:
       duplicate = True
       break

if duplicate or upper_count < 2 or digit_count < 3 :
  print("Invalid")   
else:
  print("Valid")

  • loucifsk
     + 1 comment
    import sys, re

T = sys.stdin.read().splitlines()
T = [T[1:] if len(T)<90 else T[1:91]][0]

UID = re.compile(
    r"(?!.*(.).*\1)"
    r"(?=^[a-zA-Z0-9]{10}$)"
    r"(?=(.*[A-Z].*){2,})"
    r"(?=(.*\d.*){3,})"
)

for line in T:
    if UID.search(line):
        print('Valid')
    else:
        print('Invalid')

  • pinkyy79798
     + 0 comments

    test_cases = int(input()) for i in range(test_cases): string = input() upper_count=0 digits_count=0 for ele in string: if ele.isupper(): upper_count += 1 elif ele.isdigit(): digits_count += 1
    unique_count = len(string)==len(set(string)) if len(string)==10 and unique_count and string.isalnum() and upper_count >=2 and digits_count >= 3: print('Valid') else: print('Invalid')

  • ericstricker73
     + 1 comment
    from collections import Counter

def validate(txt):

    #It must contain at least 2 uppercase English alphabet characters
    if sum([1 for x in txt if x.isupper()]) < 2:
        return False

    #It must contain at least 3 digits
    if sum([1 for x in txt if x.isdigit()]) < 3:
        return False
        
    #It should only contain alphanumeric characters 
    if not txt.isalnum():
        return False

    #No character should repeat.
    if (any(value != 1 for value in Counter(txt).values())):        
        return False

    #There must be exactly 10 characters in a valid UID.        
    if len(txt) != 10:
        return False

    
    return True

n = int(input())
for _ in range(n):
    txt = input().strip()
    print("Valid") if validate(txt) else  print("Invalid")