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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Validating UID
  5. Discussions

Validating UID

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566 Discussions

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  • nice00guy69
     + 0 comments

    WHY TF ARE PEOPLE SOLVING A REGEX PROBLEM WITHOUT REGEX?

    import re

REX = re.compile(r'^(?=(?:.*[A-Z]){2,})(?=(?:.*\d){3,})(?!.*(.).*\1)[A-Za-z0-9]{10}$')

def checker(id):
    return "Valid" if REX.match(id) else "Invalid"
        
if __name__=="__main__":
    N = int(input())
    for _ in range(N):
        print(checker(input().strip()))

  • aditya251098_ac
     + 0 comments
    def check_uid(uid):
    v='Invalid'
    if len(uid) == 10:
        if sum([0 if uid.count(i)==1 else 1 for i in uid])==0:
            if uid.isalnum():
                if sum([1 if i.isdigit() else 0 for i in uid])>=3:
                    if sum([1 if i.isupper() else 0 for i in uid])>=2:
                        v='Valid'
    print(v)
        
for _ in range(int(input())):
    check_uid(input())

  • sbk_63
     + 0 comments

    import re

    pattern = r'^(?!.(.).\1)(?=(?:.[A-Z]){2,})(?=(?:.[0-9]){3,})[a-zA-Z0-9]{10}$'

    print(*["Valid" if bool(re.match(pattern, input())) else 'Invalid' for _ in range(int(input()))], sep = '\n')

  • kajen_k27
     + 0 comments

    why is this code not working, can someone explain why?

    # Enter your code here. Read input from STDIN. Print output to STDOUT
import re 

n = int(input())

regPat = r'^(?=(.*[A-Z]){2,})(?=(.*\d){3,})(?!.*(.).*\1)[a-zA-Z0-9]{10}$'

for _ in range(n):
    if re.match(regPat, input()):
        print("Valid")
    else:
        print("Invalid")

  • dilajevolves
     + 0 comments
    import re
for _ in range(int(input())):
    uid = input()
    if len(re.findall(r'[A-Z]',uid)) >= 2 and len(re.findall(r'\d',uid)) >= 3 and uid.isalnum() and len(set(uid)) == 10:
        print("Valid")
        
    else:
        print("Invalid")