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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Validating UID
  5. Discussions

Validating UID

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recency

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548 Discussions

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  • singhshrajan
     + 0 comments
    1. import re
      1. def check(uid):
    3. if len(uid)!=len(set(uid)):
    4. return "Invalid"
    5. else:
    6. match = re.match(r'^(?=(?:.[A-Z]){2,})(?=(?:.\d){3,})[A-Za-z0-9]{10}$',uid)
    7. if match:
    8. return "Valid"
    9. else:
    10. return "Invalid"
      1. for i in range(int(input())):
    12. print(check(input()))

  • illya_muravsky
     + 0 comments
    def uid_validator(uid):
	uid = uid.strip()
	return (
		'Valid' if (
			re.fullmatch(r'^[0-9a-zA-Z]ยจ{10}', uid)
			and len(re.findall(r'[A-Z], uid) >=2)
			and len(re.findall(r'[0-9], uid) >= 3)
			and len(set(uid) == 10
		) else 'Invalid
	)

  • meetpatel692020
     + 0 comments
    # Enter your code here. Read input from STDIN. Print output to STDOUT
import re
def valid_uid(uid):
    if len(uid) !=10:
        return False
    if not uid.isalnum():
        return False
    if len(set(uid))!=10:
        return False
    if len(re.findall(r'[A-Z]',uid))<2:
        return False
    if len(re.findall(r'\d',uid))<3:
        return False
    
    return True
n = int(input())
for _ in range(n):
    uid = input().strip()
    print("Valid" if valid_uid(uid) else "Invalid")

  • pcblack777ff
     + 0 comments

    why not aceppt this? 1. import re 2. for _ in range(int(input())): 3. isha = input() 4. jinx = set(isha) 5. powder = list(isha) 6. p = r'[a-zA-Z-0-9]{1,}.\d{1,}' 7. match = re.match(p,isha) 8. if len(isha) == 10: 9. if match: 10. if len(powder) > len(jinx): 11. print('Invalid') 12. elif bool(re.match(p,isha)): 13. print('Valid')

  • cam_martin0505
     + 0 comments

    for _ in range(int(input())): guid = input() if len(guid) == 10 and guid.isalnum() and sum(c.isupper() for c in guid) >= 2 and sum(c.isdigit() for c in guid) >= 3 and len(guid) == len(set(guid)): print("Valid") else: print("Invalid")