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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Validating phone numbers
  5. Discussions

Validating phone numbers

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484 Discussions

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  • navanilgh557
     + 0 comments

    n=int(input()) for i in range(n): s=input() a='YES' if len(s)!=10 or s[0] not in '789': a="NO" if any(not j.isdigit() for j in s): a="NO" print(a)

  • sharmaj1
     + 0 comments
    #import regex package --> iterate through input, use regex "^[789]\d{9}$" to match to input using findall --> finall returns a list, if list size is not 0 then a match has been found, and print according result

import re

for i in range(int(input())):
    num = input()
    x = re.findall("^[789]\d{9}$", num)
    
    if len(x) > 0:
        print("YES")
    else:
        print("NO")

  • MisterBemo
     + 0 comments
    nums = input()

for x in range(int(nums)):
  t  =  "NO"
  num = input()
  if len(num) == 10:
    if num.isdigit():
        if int(num[0]) in [7,8,9]:
            t = "YES"
  print(t)

  • maluisamrok
     + 0 comments
    import re
N= int(input())
patron =r'^[7|8|9]\d{9}'
for i in range (N):
    s = input()
    if (re.fullmatch(patron, s )):
        print("YES")
    else:
        print("NO")

  • yashdeora98294
     + 0 comments

    Here is HackerRank Validating phone numbers in python solution - https://programmingoneonone.com/hackerrank-validating-phone-numbers-solution-in-python.html