import re

# Regular expression to match integers in the range 100000 to 999999 inclusive
regex_integer_in_range = r"^[1-9][0-9]{5}$"  # Matches a 6-digit number starting with a non-zero digit.

# Regular expression to find alternating repetitive digit pairs
regex_alternating_repetitive_digit_pair = r"(?=(\d)\d\1)"  # Lookahead for digit patterns like 121, 232, etc.

# Input reading
P = input().strip()

# Validation: Check the postal code
is_valid = (bool(re.match(regex_integer_in_range, P)) and 
            len(re.findall(regex_alternating_repetitive_digit_pair, P)) < 2)

# Output result
print(is_valid)



import re
P = input()

print (bool(re.match(regex_integer_in_range, P)) 
and len(re.findall(regex_alternating_repetitive_digit_pair, P)) < 2)

regex_integer_in_range = r"^[1-9]{1}[0-9]{5}$"
regex_alternating_repetitive_digit_pair = r"(.)(?=.\1)"


import re
P = input()

print (bool(re.match(regex_integer_in_range, P)) 
and len(re.findall(regex_alternating_repetitive_digit_pair, P)) < 2)

regex_integer_in_range = r"^[1-9]\d{5}$"
regex_alternating_repetitive_digit_pair = r"(?=(.).\1)"
import re
P = input()
print (bool(re.match(regex_integer_in_range, P)) 
and len(re.findall(regex_alternating_repetitive_digit_pair, P)) < 2)

regex_integer_in_range = r"^[0-9]{6}$"
regex_alternating_repetitive_digit_pair = r"([0-9]{1})(?=[0-9]{1}\1)"	

regex_integer_in_range = r"^[100000-999999]{6}$"	# Do not delete 'r'.

# Not more than one ARD pair
regex_alternating_repetitive_digit_pair = r"(\d)(?=\d\1)"	# Do not delete 'r'.

'''
source: StackOverflow

Explanation:

(\d): Match and capture a digit in group #1

(?=: Start lookahead

\d: Match any digit

\1: Back-reference to captured group #1

): End lookahead
'''


import re
P = input()

print (bool(re.match(regex_integer_in_range, P)) 
and len(re.findall(regex_alternating_repetitive_digit_pair, P)) < 2)